JPSC Recruitment 2019 Vacancy details: झारखंड लोक सेवा आयोग में 262 पदों पर ‘असिस्टेंट प्रोफेसर’ की भर्ती Recently JPSC Notification released and invites Sarkari Naukri Jobs application. Check Qualification & eligibility conditions, how to apply & other rules are given below Download Notification, Exam Dates Check All Details at Free Job Alert.


JPSC Recruitment 2019: झारखंड लोक सेवा आयोग में 262 पदों पर ‘असिस्टेंट प्रोफेसर’ की भर्ती

झारखंड लोक सेवा आयोग
पद का नाम: असिस्टेंट प्रोफेसर
Jharkhand Public Service Commission
Name Of Post: Assistant Professor
No. of Vacancies: 262
Advertisement No.: 03/2019
Starting Date: 23.04.2019
Last Date: 15.05.2019


Exam Eligibility: Age Limit, Qualification & Fee Details

Qualification: Post Graduation in relevant discipline.
Age Limit: Maximum 30 Years. As on 01.08.2019. Age relaxation is as per Jharkhand Govt. norms.
Application Fee: For GEN/OBC/EWS Candidates : Rs.600/-
For SC/ST Candidates : Rs.150/- through offline mode by challan form at SBI Bank or Online mode.

Useful Link for Download Notification PDF, Apply Online Application Form, Exam Date & Procedure

Download Notification: http://www.jpsc.gov.in/data/Advertisement_no_03_2019.pdf 
Apply Online Now: https://bit.ly/2Lf0SSl 
Organization Website: www.jpsc.gov.in 
JPSC Recruitment 2019

Important Link for JPSC Exams

Download Notification File PDF  
Online Form Application 
Admit Card Download
Answer Key Download
Result
Joining Letter

 Top 10 Government Jobs India 2019




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